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What is the x coordinate of the vertex? y = x2 + 4x + 4
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I haven't done this type of stuff in a long time
Completing square first y = x^2 + 4x + 4 = (x+2)^2 For the form y=(x-h)^2+k Vertex is at (h,k) Compare the general form and what you've got, what is the vertex?
or you could just use the fact that -b/2a is the x-coordinated of the vertex. and to find the y coordinate, plug that into the equation to find y.
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