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OpenStudy (anonymous):

differentiate the algebraic function (3x-2)/(2x-3)

OpenStudy (anonymous):

would using product rule with 3x-2 * 1/(2x-3) work?

OpenStudy (anonymous):

other wise use quotient rule look it up but It is way harder to memorize :P

OpenStudy (anonymous):

idk all i know is that the answer is 5/(2x-3)^2

OpenStudy (anonymous):

use qoutient rule and just plug it into the formula

OpenStudy (anonymous):

(3x-2)/(2x-3) g h

OpenStudy (anonymous):

oh that would make sense thanks alot :D

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