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OpenStudy (anonymous):
differentiate the algebraic function (3x-2)/(2x-3)
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OpenStudy (anonymous):
would using product rule with 3x-2 * 1/(2x-3) work?
OpenStudy (anonymous):
other wise use quotient rule look it up but It is way harder to memorize :P
OpenStudy (anonymous):
idk all i know is that the answer is 5/(2x-3)^2
OpenStudy (anonymous):
use qoutient rule and just plug it into the formula
OpenStudy (anonymous):
http://upload.wikimedia.org/wikipedia/en/math/a/c/e/acedbab55b97d9c1bb42c57302faea9a.png
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OpenStudy (anonymous):
(3x-2)/(2x-3) g h
OpenStudy (anonymous):
oh that would make sense thanks alot :D
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