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Area of the region under 1+sinx from pi/6 to 5pi/6
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intigrate abs(1+sin x) from pi/6 to 5 pi/6 And you might wanna check for absolute values so i made it that just in case.
I did this, but I get a weird answer.
Not the textbook one.
if you used calculator to evaluate make sure you in radians.
try it without the abs() and I get 3.826445
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Can you show steps?
well integral of 1-sin(x) is just x-cos(x) -a+cos(a)+b-cos(b) where a is starting value and b is final value
Okay I did this: (5pi/5 - cos5pi/6) - (pi/6 - cospi/6) What am I doing wrong?
|dw:1338351147427:dw|
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