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A person weighs 500 N. If he falls a vertical distance of 15 meters into a pile of hay, what is the average force exerted by the hay if the person stops in 0.12 seconds?
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take g=10, we get m=50 use the use kinematic for falling body to calculate the velocity \[ v = \sqrt{2gh} \] and \[ v = a t \] so we get \[ F = ma = \frac{m}{t}\sqrt{2gh} \]
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