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Which of the following is a solution to the inequality below?
x^2/3^2 - y^2/4^2
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A. (-8, -2) B. (3, 1) C. (4, 0) D. (-12, 4)
\[\large \frac{x^2}{3^2} - \frac{y^2}{4^2} \le 1?\]
yes! i think i can sub the numbers in individually.. correct?
im thinking 3,1
3,1 1ill give you 1 - 1/4 = 3/4 and that is less than 1 so correct
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