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Mathematics 22 Online
OpenStudy (anonymous):

How would I solve this:

OpenStudy (anonymous):

OpenStudy (cwtan):

(x+3)-2(3x+9)=2(x+3)(3x+9)

OpenStudy (cwtan):

(x+3)-2(3(x+3))=2(x+3)(3(x+3)) (1-6)(x+3)=6(x+3)^2 -5(x+3)=6(x+3)^2 Let x+3=y 6y^2+5y=0 y(6y+5)=0 y =0, 6y+5=0

OpenStudy (anonymous):

but what is x equal to

OpenStudy (apoorvk):

okay, can you write 3x+9 as 3(x+3)? You can right? So you equation changes to:|dw:1338359413787:dw| can you proceed now?

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