Question

solve this systems of linear equations using any algebraic method. 3y=11-2x
3x=y-11

Answer 1

3x = y - 11

therefore

y = 3x + 11

substitute this into the first equation

3(3x + 11) = 11 - 2x

9x + 33 = 11 - 2x
9x + 2x = 11 - 33
11x = -22

x = -2

Answer 2

if i substitute that to the second equation

3(-2) = y - 11

-6 = y - 11
-6 + 11 = y

y = 5