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Mathematics 24 Online
OpenStudy (anonymous):

Hi guys. How would you approach this question? Antiderivative of (sinx)+(xcosx)/xsinx

OpenStudy (anonymous):

\[\large \int\limits sinx+ \frac {xcosx}{xsinx} dx\] this?

OpenStudy (anonymous):

otherwises if u meant ((sinx)+(xcosx))/xsinx then take xsinx as u and the the answer reduces to ln(xsinx) +c

OpenStudy (anonymous):

|dw:1338360122691:dw| find it and get your answer..

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