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OpenStudy (anonymous):
OpenStudy (anonymous):
Should I also link the options [a,b,c,d] which are graphs
OpenStudy (unklerhaukus):
asymptotes are at the excluded values
OpenStudy (anonymous):
OpenStudy (anonymous):
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OpenStudy (anonymous):
OpenStudy (anonymous):
OpenStudy (anonymous):
To find the vertical asymptotes, that means the x values that will have no solution. This is possible when the denominator of the function given is 0. Since x/0 is undefined. So find the the value of x that will result in a 0 in the denominator.
2x+48 = 0
2x=-48
x=-24
OpenStudy (anonymous):
Is the expression given wrong? is the denominator 2x+ 4 rather than 2x+48.
OpenStudy (anonymous):
um no it is not wrong
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OpenStudy (anonymous):
waiyt hold on
OpenStudy (anonymous):
OpenStudy (anonymous):
that is the correct question SORRY to confuse u :(
OpenStudy (anonymous):
@tiaph sorry for posting the wrong equation in the beginning but this one is the right one
OpenStudy (anonymous):
thus the vertical asymptote is x=2 (since 2-2=0)
And horizontal asymptote is just y = -3
Option a is ur answer.
If you are not sure how i got the answer. just ask.
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OpenStudy (anonymous):
its ok once my brother is home tomorrow i will ask him to help me out with the questions I couldnt figure out btw Medal given thanks