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Mathematics 8 Online
OpenStudy (anonymous):

Identify the asymptotes of the graph.

OpenStudy (anonymous):

OpenStudy (anonymous):

Should I also link the options [a,b,c,d] which are graphs

OpenStudy (unklerhaukus):

asymptotes are at the excluded values

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

OpenStudy (anonymous):

To find the vertical asymptotes, that means the x values that will have no solution. This is possible when the denominator of the function given is 0. Since x/0 is undefined. So find the the value of x that will result in a 0 in the denominator. 2x+48 = 0 2x=-48 x=-24

OpenStudy (anonymous):

Is the expression given wrong? is the denominator 2x+ 4 rather than 2x+48.

OpenStudy (anonymous):

um no it is not wrong

OpenStudy (anonymous):

waiyt hold on

OpenStudy (anonymous):

OpenStudy (anonymous):

that is the correct question SORRY to confuse u :(

OpenStudy (anonymous):

@tiaph sorry for posting the wrong equation in the beginning but this one is the right one

OpenStudy (anonymous):

thus the vertical asymptote is x=2 (since 2-2=0) And horizontal asymptote is just y = -3 Option a is ur answer. If you are not sure how i got the answer. just ask.

OpenStudy (anonymous):

its ok once my brother is home tomorrow i will ask him to help me out with the questions I couldnt figure out btw Medal given thanks

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