Question

1. Simplify (b2c +7bc – 3) – (12b2c – 2bc + 5).
–11bc2 + 9bc – 8
–11b2c + 9bc – 8
13b2c + 5bc + 2
–11b2c + 5bc + 2
2. Simplify 3fg(f2g + 5f – 4).
3f2g2 +15fg – 12
3f3g3 + 15f2g – 12
3f3g2 + 15f2g – 12
3f3g2 + 15f2g – 12fg

Answer 1

question(1)
–11b2c + 9bc – 8
question(2)
3f3g2 + 15f2g – 12fg

Answer 2

Thank You so much :D

Answer 3

we see here in question 1
I add the same terms together
(b2c with b2c) and (bc with bc)
but, I cannot add (b2c with bc)

question2
I multiplied 3fg with the every component
ex.
3fg(g) = 3fgg= 3fg2
3fg(4fg)= (3)(4)(f)(f)(g)(g)=12f2g2

best of luck with your future studies

Answer 4

Thank you:D