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The points A and B are located on the circumference of a circle having diameter 54 feet. If C is the center of the circle, what is the distance from point A to point B along a straight line? (1 point) 18 feet 27 feet 32.24 feet 38.18 feet
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CA=CB=radius = 54/2 = 27 feet AB^2 = CA^2 + CB^2 = 2(27^2) so AB = 27sqrt2 = 38.18 feet
That's what I thought it was. Thanks again!!
my pleasure :)
just apply pythagoras theorem. I thik u got it.
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