The faces of a tetrahedron die are numbered 1 to 4. If each of the 4 sides is equally likely to land down, what is the probability that the 2 does not end up face down?

Question

anonymous · Answer

$\frac 34 $ ?

anonymous · Answer

well, the chance for ANY number to land is 1/4 - (landing side)/(total sides)

the chance that 2 will be the number that WON'T land, that is only 1,2, and 4 can land, means it will be 3/4

because the amount of sides that could land are 3, and the total sides are 4

thus 3/4

anonymous · Answer

that is only 1,3,4* can land lol woops

anonymous · Answer

The probability of 2 end up face down is $ \frac 14 $. Hnece probability of 2 not landing face down is $ 1 - \frac 14  =\frac 34  $.

anonymous · Answer

Hence*