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sqaure root of 10xy divide by square root of 2x^3
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it can be rewritten as \[\frac{\sqrt{10xy}}{\sqrt{2x^3}} = \sqrt{\frac{10xy}{2x^3}}\] cancel common factors to obtain your answer.
so 5x^2y?
not quite its \[\sqrt{\frac{5y}{x^2}}\]
thanks
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