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The volume of two similar solids is 1331 m3 and 729 m3. The surface area of the larger solid is 605 m2. What is the surface area, in square meters, of the smaller solid? Explanation and answer please or just answer :)
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81 121 305 405
305?
cubert 1331 / cubert 729 gives ratio of corresponding lengths of similar objects the surface areas will be in ratio of squares of the above values
cubert 1331 = 11 and of 729 = 9 ratio of 11:9 so areas will be in ratio 121 : 81
so 121/81 = 605/ x find x
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405? and that's the answer?
yes
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