Ask
your own question, for FREE!
Mathematics
2 Online
1/2(2x-3)+2/3(4x+1)=3-1/4(2x+2/3)
Still Need Help?
Join the QuestionCove community and study together with friends!
Let's multiply each term fy 12 and thereby clear all the fractions.
\[12\times\frac{1}{2}(2x-3)+12\times\frac{2}{3}(4x+1)=12\times3-12\times\frac{1}{4}(2x+\frac{2}{3})\]
\[6(2x-3)+8(4x+1)=36-3(2x+\frac{2}{3})\]
\[12x-18+32x+8=36-6x-6\]
Perhaps you can take it from there.
Still Need Help?
Join the QuestionCove community and study together with friends!
thank you so much
yw
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Twaylor:
Time flies doesn't it? I tried to not be the second squeaky wheel of the household and ended up hurting myself and others severely.
clllaaaaaire:
any tips? the quality isn't the best because I am using this site on my computer
Midnight97:
Kinda a roleplay story between me and my friend enjoy... Part one Forgive me for all the screenshots.
StevenisGhost:
what type of song should I make next, and will y'all go check out my new song on
Midnight97:
My drawing sure changed over the years look at these two pictures from 2024 to no
EdwinJsHispanic:
"poem" love is So Beautiful to have. But it's so hard to have. At this point I don't know whether its worth the wait Or if it's just millions of miles to re
EdwinJsHispanic:
"poem" love is So Beautiful to have. But it's so hard to have. At this point I don't know whether its worth the wait Or if it's just millions of miles to re
Breathless:
I don't know if this would be considered art, but its close enough I believe, Any
1 day ago
12 Replies
2 Medals
2 weeks ago
2 Replies
0 Medals
2 weeks ago
2 Replies
1 Medal
1 week ago
6 Replies
2 Medals
2 weeks ago
6 Replies
1 Medal
3 weeks ago
3 Replies
0 Medals
3 weeks ago
0 Replies
0 Medals
3 weeks ago
3 Replies
0 Medals