Can someone please help me? A rectangular lot has a perimeter of 350 feet. An expensive fencing along the lot's lengths costs $27.60 per foot. An inexpensive fencing along the widths costs $4.70 per foot. The total cost of the fencing comes to $4,622. What are the lot's dimensions?
You need to set up the two equations. Let L be length and W be width. Perimeter = 350 ft. So, what is that in terms of L and W?
2L+2w=350 ?
YES!!
Now, the second equation. Cheap fence using along widths and expensive used along widths. What is the cost equation in terms of L and W?
2(27.60)+2(4.70)=4622
Well....its is 2L(27.60) + 2W(4.70) = 4622. => 55.20L + 9.40W = 4622 So, now you have two equations in two variables. Solve them using substitution or elimination.
sweet thanks!
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