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in meters the sides of a triangle measure 7, 9 and 11. find the perimeter of a similar triangle in which the longest side has a length of 44 meters
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you could set up a propertion for example : 11/9 = 44/x then solve for x, which would be 36 11/7 = 44/x x = 28 then just add up all the sides 44+36+28 so the perimeter is 108
@bianca101 you need any more help?
thanks & yes ; in a right triangle the length of a hypotenuse is 20 centimeters and the length of one leg is 16 centimeters find the length of the other leg
ok so do know the PYTHAGOREAN-THEOREM if not it A^2 + B^2 = C^2|dw:1338433014739:dw|
can you do the rest?
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yes thank you
sure no problem
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