Question

Fill in the missing term so that the quadratic equation has a graph that opens up, with a vertex of (– 2, – 16), and x intercepts at x = -6 and x = 2. (Do not include the negative sign in your answer.)

Answer 1

Do you want the general form or standard form?

Answer 2

general hun

Answer 3

(x + 6)(x - 2) = x^2 + 4x - 12 = 0
x^2 + 4x = 12
(x + 2)^2 = 16
y = (x + 2)^2 - 16