Question

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Answer 1

first subtract
\[\frac{1}{3x+9}-\frac{2}{x+3}=\frac{1}{3x+9}-\frac{6}{3x+9}=\frac{-5}{3x+9}\]
then you have
\[\frac{-5}{3x+9}=2\] so
\[-5=2(3x+9)\]
\[-5=6x+18\] and you should be good from there

Answer 2

\[-23=6x\]
\[x=-\frac{23}{6}\] is the finish

Answer 3

yw