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please help! find the vertex, focus,and directrix of the parabola and sketch its graph (x+3/2)^2=4(y-2)
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are they as the following vertex (-3/2,2) focus (-3/2,3) directrix is y-1 =0
how Exactly did u get that??
are the ans correct
yeah according to the back of my book :)
u hv to use shifting of the origin that is x+3/2=x' and y-2=y' and then use standard formulas for parabola
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c thats wat confuses me
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