Question

Can someone help?

Answer 1

\[\csc x = \frac{3}{2}\] it says that \[\csc x = \frac{3}{4y}\] too so we equate them \[\frac{3}{2} = \frac{3}{4y} \implies 12y = 6 \implies y = \frac{1}{2} \]

Answer 2

Omg, thats what i thought. thaks so much.