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Mathematics 9 Online
OpenStudy (anonymous):

Please i need the question b) only thanks

OpenStudy (anonymous):

http://screencast.com/t/CciNQSaVQjmD

OpenStudy (anonymous):

@ParthKohli @AccessDenied @Aadarsh

OpenStudy (anonymous):

easy 1minute I am answering u now

OpenStudy (anonymous):

Angle CDX = 56, so, 1/2 angle CDX = angle XDB = 28 dehrees

OpenStudy (anonymous):

okay thanks :)

OpenStudy (anonymous):

they never say CDX = XDB

OpenStudy (anonymous):

so you have to prove by complimentary angles

OpenStudy (anonymous):

because it is a parellelogram we can prove right?

OpenStudy (anonymous):

i used equal angles to prove it

OpenStudy (anonymous):

show me ur method?

OpenStudy (anonymous):

Given, CD is parallel to EB, so angle CDX = angle EDX = 56 degrees. So, angle DXB = 180 - 56 = 124 degrees

OpenStudy (anonymous):

So, angle XBD = 180 - (124+28) = 28 degrees = angle BDX Hence, traingle BDX is isosceles

OpenStudy (anonymous):

EB // DC => BDC = EBD EBD = EAD => EA // BD => AEB = ADB => EBD = EBD => BDX isosceles

OpenStudy (anonymous):

thanks once again guyz :D

OpenStudy (anonymous):

no pb

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