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Please i need the question b) only thanks
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@ParthKohli @AccessDenied @Aadarsh
easy 1minute I am answering u now
Angle CDX = 56, so, 1/2 angle CDX = angle XDB = 28 dehrees
okay thanks :)
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they never say CDX = XDB
so you have to prove by complimentary angles
because it is a parellelogram we can prove right?
i used equal angles to prove it
show me ur method?
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Given, CD is parallel to EB, so angle CDX = angle EDX = 56 degrees. So, angle DXB = 180 - 56 = 124 degrees
So, angle XBD = 180 - (124+28) = 28 degrees = angle BDX Hence, traingle BDX is isosceles
EB // DC => BDC = EBD EBD = EAD => EA // BD => AEB = ADB => EBD = EBD => BDX isosceles
thanks once again guyz :D
no pb
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