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log5 x=4logx 5+3
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Use the same principle that I've thought you just now
but i can't understand...can you explain to me more efficiently...
how you factor that...
can you help me...
\[\log_5 x=4\log_x 5+3\] \[\log_5 x=\log_x 5^4+3\] \[\log_5 x=\frac{\log_55^4}{\log_5x}+3\] \[\log_5 x=\frac{4}{\log_5x}+3\]
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