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Mathematics 7 Online
OpenStudy (anonymous):

log5 x=4logx 5+3

sam (.sam.):

Use the same principle that I've thought you just now

OpenStudy (anonymous):

but i can't understand...can you explain to me more efficiently...

OpenStudy (anonymous):

how you factor that...

OpenStudy (anonymous):

can you help me...

sam (.sam.):

\[\log_5 x=4\log_x 5+3\] \[\log_5 x=\log_x 5^4+3\] \[\log_5 x=\frac{\log_55^4}{\log_5x}+3\] \[\log_5 x=\frac{4}{\log_5x}+3\]

sam (.sam.):

I'm sure you can solve it now

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