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what is the value of
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equation comin up
\[_4{P}_{2}\]
6 8 12 24
im not sure...
HINT:nPr=(n!)/(n-r)!
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\(\Huge \text{nPr}=\frac{n!}{(n-r)!}\)
...now i am confused
wait is the answer C...??
HINT: \(\Huge \text{n!}=n*(n-1)!\)
\(0!=1, 1!=1\)
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@SamiFarooq it's C...
ok good
Medal given thanks guys i have one more question like this..its a little but different though
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