Question

solve by the square root method
(x-3)^2+33=0
not sure if my answer is correct I got x=+-the square root of 6times 7

Answer 1

The answershould be a complex number.

Answer 2

what is meant by square root method?

Answer 3

This has no real roots. It has 2 complex roots
\[(x-3)^2 =-33 = i^2 33\\
x-3 =\pm i \sqrt {33}\\
x = 3\pm i \sqrt {33}\\
\]