Question

Solve. 3x2 = 33x – 27

Answer 1

\[3x^2-33x+27=0\]
the roots are:
\[[-(-33)\pm \sqrt{33^2-4*3*27}]/2*3\]

Answer 2

\[x1=(33+\sqrt{765})/6\]
\[x2=(33-\sqrt{765})/6\]

Answer 3

what is the answer?

Answer 4

because for my answer choices i cant seem to figure which is correct

Answer 5

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