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OpenStudy (anonymous):
solve; 2x^2+12x+16=0
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OpenStudy (lgbasallote):
\[2x^2 + 12x + 16 = 0\] \[2(x^2 + 6x + 8) = 0\] \[2(x+4)(x+2) = 0\] therefore \[x = -4\] \[x = -2\]
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