Question

the value of (sin 60)(cos 60) is

Answer 1

are you asked to use trig theorems? or just evaluate it?

Answer 2

coz idk theorems...but i can give you the value

Answer 3

ok

Answer 4

\[\sin (60) = \frac{\sqrt 3}{2}\] \[\cos (60) = \frac{1}{2}\] therefore \[(\sin 60)(\cos 60) = \frac{\sqrt 3}{2} \times \frac{1}{2} = \frac{\sqrt 3}{4}\]

Answer 5

Ty ^^