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Find the equations, in slope-intercept form, of the asymptotes to the conic whose equation is 16y2 - 4x2 - 128y + 64x - 64 = 0 please help me!!
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Completing the square, (y - 4)^2/4 - (x - 8)^2/16 = 64 Slope is rise/run. Therefore, the equations of the asymptotes are: y = ±1/2x
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