h(t)=-16t^2+32t+3
1. a) What are the coordinates of the vertex of the parabola?
b) What do the coordinates of the vertex of the parabola mean in the context of this problem?
2. How high off the ground will the ball be after 2 seconds?
3. Why is the height the same at .5 seconds and 1.5 seconds and what is the height?
4. a) How long is the ball in flight? Round answer to nearest hundredth.
b) Which formula, process, etc. did you use to solve this problem?

Question

h(t)=-16t^2+32t+3
1. a) What are the coordinates of the vertex of the parabola? 
b)  What do the coordinates of the vertex of the parabola mean in the context of this problem?
2. How high off the ground will the ball be after 2 seconds? 
3. Why is the height the same at .5 seconds and 1.5 seconds and what is the height?
4. a) How long is the ball in flight?  Round answer to nearest hundredth.
b)  Which formula, process, etc. did you use to solve this problem?

anonymous · Answer

to get the vertex of the parabola, let v=-b/(2a) = -32/(2*(-16)) = 1.  it is at this time, t=1 where the vertex occurs.  to find height at this time, plug into the equation for h.

anonymous · Answer

thats what my teacher said but i just kept gettin confused

amistre64 · Answer

h(t)=-16t^2+32t+3

h(t=1)= -16(1)^2+32(1)+3
         = -16+32+3
         = ??

amistre64 · Answer

what are you gettiing confused about?

anonymous · Answer

i get lost when i have to distribute and do -b/(2a) it takes to long to solve for and i get lost

amistre64 · Answer

focus!! :)

anonymous · Answer

trying nd thanks :)

anonymous · Answer

the answer u gave.. what number does that solve for?

amistre64 · Answer

first one i think, dpalnc showed how to get the t coordinate, and the h coordinate is just the solution to that

anonymous · Answer

okay.

amistre64 · Answer

and i think b as well by default

anonymous · Answer

can u guys come back and help