Question

If cos A = .5417 and A is an angle between 0 and 90, find A. Round to the nearest tenth of a degree

Answer 1

A must be near pi/3

Answer 2

i dont get you sorry can you explain

Answer 3

please help me

Answer 4

cos(pi/3)=1/2

Answer 5

try use taylor

Answer 6

i dont get the answer

Answer 7

why dont you use calculator

Answer 8

because my calculator is simple i cant type it in

Answer 9

\[f(x)=f(x0)+(x-x0).f'(x0)+(x-x0)^{2}/2!.f''(x0)+....\]

Answer 10

x0=pi/3;x=.5417

Answer 11

would you mind telling me the answer

Answer 12

i have no calculator now

Answer 13

c:

Answer 14

:D

Answer 15

0.5417=1/2+(x-pi/3).(-sen(pi/3))+(x-pi/3)²/2!.-(cos(pi/3))

Answer 16

solve for x

Answer 17

your gona say im so dumb but i dnt know how

Answer 18

its a second degree polynomial.Do you know baskara formula?

Answer 19

nope

Answer 20

A=57.20

Answer 21

it's in degrees

Answer 22

A. 32.0
B. 38.7
C. 51.3 but dude my answer choices are these
D. 90.0