Question

What is the equation of a circle that passes through point J(6, 4) and has center K (1, -8).

Answer 1

find the radius by doing the distance formula between (6,4) and (1, - 8)

Answer 2

then use the equation of the circle \[(x-h)^2 + (y-k)^2 = r^2\] do you need more hints?

Answer 3

So do you put the numbers given in that equation?

Answer 4

yup...
x1 = 6
x2 = 1
y1 = 4
y2 = -8

Answer 5

okay haha thank you!

Answer 6

ask me if you get stuck

Answer 7

alright :)

Answer 8

I got 85 but I don't think it's right.