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obtain a family of solutions for \[(x-2y)dx + (2x+y)dy = 0\]
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put it in this form first: dy/dx=-x+2y/2x+y then devide by x the right side dy/dx=-1+2(y/x)/2+(y/x) make variable change y/x=u y=ux dy/dx=u+x(du/dx) substitute in the DE and solve by separating variables
why cant you sub from the start?
you could, just is more clear other way
i see
since you don't mess with differentials
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is u + x(du/dx) = udx + xdu?
yes
great..thanks
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