Question

Can someone help me with this sin cos problem?

Answer 1

THis

Answer 2

what is you favourite, sine cosine or tangent?

Answer 3

\[\sin B= \frac{\text{opposite}}{\text{hypotenuse}}=\frac{4}{5} \quad\rightarrow\qquad B=\arcsin \left(\frac45\right)\]
\[\cos B= \frac{\text{adjacent}}{\text{hypotenuse}}=\frac{3}{5}\quad\rightarrow\qquad B=\arccos \left(\frac35\right)\]
\[\tan B= \frac{\text{opposite}}{\text{adjacent}}=\frac{4}{3}\quad\rightarrow\qquad B=\arctan \left(\frac43\right)\]