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Write the quadratic equation in general quadratic form below. 3x^2 + 6x = 12
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here 3x^2 + 6x -12=0 so a=3 , b=6 and c =-12 quadratic formula is \[-b \pm \sqrt{b^2-4ac}/2a \] insert values and calculate :)
answers are x= 1.2 , -3.2
ohh okay,l thanks :)
thanks :P
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