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Solve the word problem. One leg of a right triangle is 96 inches. Find the hypotenuse and the other leg if the length of the hypotenuse exceeds 2 times the other leg by 4 inches. Hypotenuse = ......inches leg =...... inches
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\[a ^{2}*b ^{2}=c ^{2}\]
a = 96 \[c=2b+4\] \[96^{2}+b ^{2}=(2b+4)^{2}\]
\[9,216+b ^{2}=4b ^{2}+16b+16\]
understand so far?
yeah, I think :)
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\[3b ^{2}+16b-9,200=0\]
\[B=52.77499 \] solve C... \[C=\sqrt{a ^{2}+b ^{2}}\]
\[C=2b+4\] \[C=2*52.77499+4\] \[C=105.54999+4\] \[C=109.54999\] the answer is 109.5499 or Round up 110
understand now?
yes, thank you so much! :D
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np :D
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