Question

find the Diameter of the circle for Bc=17 andDC=30

Answer 1

join OD



let the radius of the circel be x

the radius and tangent OD and CD intersect at right angles so you can use pythagoras' theorem

\[30^2 + x^2 = (17+x)^2\]

or

\[900 + x^2 = 289 + 34x + x^2\]

simplifying gives

34x = 611

so x = 611/34

which is the radius

diameter is 2 *(611/34)

d = 35.94