Ask your own question, for FREE!
Mathematics 12 Online
OpenStudy (anonymous):

Solving Rational Equations Help!

OpenStudy (anonymous):

7. Solve https://www.connexus.com/content/media/527936-7112011-15747-PM-680351122.jpg . (1 point) 8 0 −1 −8

OpenStudy (anonymous):

the problem is in the link

OpenStudy (anonymous):

all yours parth...:)

Parth (parthkohli):

lol

Parth (parthkohli):

So, you have to take the constant i.e 1 on the other side and change the sign.

OpenStudy (anonymous):

I have two problems I dont get you can each do one :)

OpenStudy (anonymous):

Parth is Sifu Parth in these matters of algebra....

OpenStudy (anonymous):

lol ok

OpenStudy (anonymous):

I dont really understand what you just said about the constant @ParthKohli

Parth (parthkohli):

Or you may say that you're adding 1 to both sides. \(\Large \color{Black}{\Rightarrow {x - 5 \over x} = {x + 3 \over x} + 1 }\) Now subtract \(x + 3 \over x\) from both sides. \(\Large \color{Black}{\Rightarrow {x - 5 \over x} - {x + 3 \over x } = 1 }\) \(\Large \color{Black}{\Rightarrow {(x - 5) - (x + 3) \over x} = 1}\)

OpenStudy (anonymous):

ok

Parth (parthkohli):

Now multiply both sides by x. \( \color{Black}{\Rightarrow x = (x - 5) - (x + 3) }\) \( \color{Black}{\Rightarrow x = x - 5 - x - 3 }\) \( \color{Black}{\Rightarrow x = -8 }\)

Parth (parthkohli):

@dpaInc Lol I know a lot more other things than algebra ;P

OpenStudy (anonymous):

ok thanks! I have one more question!

OpenStudy (anonymous):

i bet u do...:)

OpenStudy (anonymous):

shh!!

OpenStudy (anonymous):

8. Solve https://www.connexus.com/content/media/527936-7112011-15712-PM-225344645.jpg . (1 point) −10 −1 0 10

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!