A baseball is thrown upward from ground
level with an initial velocity of 46 feet per
second, and its height h in feet is given by
h = −16t^2+ 46t, 0 ≤ t ≤ 3
where t is the time in seconds. Suppose you
are told that the ball reaches a height of 64
feet. Is this possible?

Question

A baseball is thrown upward from ground
level with an initial velocity of 46 feet per
second, and its height h in feet is given by
h = −16t^2+ 46t, 0 ≤ t ≤ 3
where t is the time in seconds. Suppose you
are told that the ball reaches a height of 64
feet. Is this possible?

mertsj · Answer

replace h with 64 and see if you get any real solutions for t.