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Solve 10x^4-27x^2+5=0
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\[x \approx 4472, - 0.4472, 1.5811, 1.5811 \] This is in decimal form.
is x= +/- sqrt (5/2) correct?
this is factorable
x\[x = \sqrt{5}/5\]
forgot x^2 you'll need to use a u sub though... if you did that, i'm pretty sure you have the right answer
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i got that as well as +/- sqrt 10/2
\[(2x^2-5)(5x^2-1)=0\] solve i wrote it wrong in the equation editor
+/ - ^4(sqrt)10 , 3(sqrt)5^2 / 5
^4(sqrt)10 is the 4th root of 10 where 4 is written above the radicand
correction: do not place parenthesis around sqrt
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your first answers are right \[+-\sqrt{5}/5\] and \[+-\sqrt{10}/2
no need for 4th roots i wrote it wrong. i thought you notice must haven ot
oh sorry
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