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Mathematics 7 Online
OpenStudy (anonymous):

what around your house/in school would be the size of 22√5 ft?

OpenStudy (anonymous):

according to the unit theyre using, are they measuring volume?

OpenStudy (anonymous):

weight?, temperature?, area?

OpenStudy (anonymous):

area of something

OpenStudy (anonymous):

you sure? what's the unit?

OpenStudy (anonymous):

Find the perimeter of a rectangular object which has a length of square root of 180 feet and a width of square root of 125 feet. Part 2: Explain, in complete sentences, how you arrived at the answer and give the final solution in simplified radical form.

OpenStudy (anonymous):

thats the information i am given

OpenStudy (anonymous):

then i simplified it out to 22 squareroot5

OpenStudy (anonymous):

did i do this correctly? 2(squareroot180+squareroot125) simplify to 2(6squareroot5+5squareroot5) 6+5=11. so 2(11squareroot5) Perimeter=22squareroot5 ft

OpenStudy (anonymous):

i thought we were answering the question posted... and that is what is 22sqrt5 feet that is around your house... why don't u use that as an example....

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