What are the slopes of the asymptotes for the hyperbola with the equation
(x - 2)^2 /16 - (y + 3)^2 /25 = 1?

+/- 16/25
+/- 25/16
+/- 5/4
+/- 4/5

NOTE: (+/-) plus or minus.

Question

What are the slopes of the asymptotes for the hyperbola with the equation
(x - 2)^2 /16 - (y + 3)^2  /25  = 1?

	+/- 16/25
	+/- 25/16
	+/- 5/4
	+/-  4/5

NOTE: (+/-) plus or minus.

anonymous · Answer

looks like +/- 5/4 to me.

anonymous · Answer

the number under the y^2 is the square of the distance up and down from the center; likewise, the number under the x^2 is the distance left and right from the center.