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f(x) = -12x + 1 g(x) = 6x ^2 + 5x - 17 Find f(g(-8))
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First substitute in G(x) x with 8 then the result substitute instead of x in the function F(x) .
\( \color{Black}{\Rightarrow f(6x^2 + 5x - 17) }\) \( \color{Black}{\Rightarrow-12(6x^2 + 5x - 17) + 1 }\) Simplify and operate on like the term(s).
@ParthKohli : Its G(-8) not G(X)
Whatever you will get, you will have to replace x with -8.
-4883?
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We always have wolfram to check the answer :)
wolfram?
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