Question

8x2 + 4x, for x = 4

Answer 1

\[8\times2+4(4)\]\[(16)+(16)\]\[32\]

Answer 2

I think the x in 8x^2 is supposed to be to the 2nd, so 8(4^2)

Answer 3

8(4^2) +4*4=8*16+16=?

Answer 4

In that case, it would be as follows:
\[8\left( 4 \right)^{2} + 4\left( 4 \right)\]\[8\left( 16 \right) + (16)\]\[128 + 16\]

Answer 5

whoops, left out the answer which is \[144\]