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OpenStudy (anonymous):
A normal of the line...?
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OpenStudy (anonymous):
Normal of the line that is perpendicular to 2x-4y+5=0?
OpenStudy (anonymous):
well normal just means perpendicula
OpenStudy (anonymous):
find the slope and the slope is if you have y/x then something perpendicular to it is - x/y Just flip over the slope and mulitply by negative one.
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