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solve by substitution x + 3y = -4 4x + 5y = 5
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what would you like to substitute?
x + 3y = -4 ....................(1) 4x + 5y = 5.....................(2) from equation (1) x= -4-3y substitute for x in (2) 4(-4-3y) + 5y = 5 -16 - 12y + 5y = 5 -7y = 21 y = 21/-7 = -3 now plug y = -3 into equation (1) to get x
or since we have an equation for x in terms of y; just use that one either-or
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