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If g(x) = 3x + 5, what is g-1(x)? a. x minus 5, over 3 b. x plus 5, over 3 c. x plus 3, over 5 d. x minus 3, over 5
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You Let y=3x+5 \[y-5=3x\] \[x=\frac{y-5}{3}\] \[g^{-1}(x)=\frac{y-5}{3}\]
so its x-5/3?
yes
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