Find the vertex of the parabola given by y=x^2-10x+17?????????????

Question

swissgirl · Answer

R u suppossed to complete teh square?

anonymous · Answer

No clue I typed out the whole question

swissgirl · Answer

no liek what method shld u be using? what have u recently been learning in class?

anonymous · Answer

This is for the final I have never seen this before in my life

swissgirl · Answer

ummm so I can give u a shortcut and hope this is the method they want

anonymous · Answer

Anything helps

swissgirl · Answer

ok well ur equation is in the format ax^2+bx+c
so our x value of our vertex is -b/2a
which is -(-10)/2(1)=5
so the x value of our vertex is 5
Then we plug in 5 into our x an we figure out what our y value of our vertex is:
5^2-10(5)+17=-8
So our vertex is at (5,-8)

swissgirl · Answer

umm if you dont understand nething just ask

anonymous · Answer

Thank you so much!!!!!!!!!