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Physics 13 Online
OpenStudy (anonymous):

You roll a number cube once. Then you roll it again. What is the probability that you will get a 6 on the first roll and a number greater than 3 on the second roll?

OpenStudy (kropot72):

\[P=\frac{1}{6}\times (\frac{1}{6}+\frac{1}{6}+\frac{1}{6})\]

OpenStudy (anonymous):

Thank you.

OpenStudy (kropot72):

You're welcome :)

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