Question

Find the x-intercepts. f(x)=x^2+6x+10

Answer 1

I got -2, -4

Answer 2

Weird...
Put f(x)=0
x^2+6x+10 =0
Use quadratic formula
\[x= \frac{-b\pm \sqrt {b^2 - 4ac}}{2a} = \frac{-6\pm \sqrt {6^2 - 4(1)(10)}}{2(1)} = \frac{-6\pm \sqrt {-4}}{2} = -3\pm i\]